Hello all,
I just purchased this scope for my 6.5X284; I know its not a 204 but thought that you guys might be able to help. My question is what does .18 inches per click translate to? I would like to make some come-up sheets for it from the JBM program, but I am unsure as what to input for clicks. Thanks in advance!
Carlyle
Swarovski PH6-24X50
Swarovski PH6-24X50
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Re: Swarovski PH6-24X50
Never heard of that click value on a scope. Are you sure it shouldn't be 1/8 instead of .18?
Many scopes are 1/4 in clicks at 100 yards and the target scopes with higher power are often 1/8 inch per click at 100 yards. Check this out before going any farther.
Many scopes are 1/4 in clicks at 100 yards and the target scopes with higher power are often 1/8 inch per click at 100 yards. Check this out before going any farther.
Re: Swarovski PH6-24X50
I would agree, but I am sure that it is .18 inches per click. Sorry this is long but it is from the Swarovski Optik.
Habicht PV
6-24x50 P
Magnification 6-24x
Objective lens diameter (mm) 50
Objective lens diameter (in) 1.97
Exit pupil, diameter (mm) 8.3-2.1
Exit pupil, diameter (in) 0.33-0.08
Eye relief (mm) 80
Eye relief (in) 3.15
Field of view, real (m/100 m) 6.2-1.8
Field of view, real (ft/1000 yds) 18.6-5.4
Field of view, real (degree) 3.5-1
Field of view, apparent (degree) 23.2
Transmission (%) 90
Twilight factor (DIN 58388) 17-35
Impact point correction per click (mm/100 m) 5
Impact point correction per click (in/100 yds) 0.18
Max. elevation/windage adjustment range (ft/100 yd E: 3.6/W: 2.1
Objective filter thread M 55 x 0.75
Length, approx. (mm) 392
Length, approx. (in) 15.43
Weight, approx. (oz) 23.6
Weight, approx. (oz) 18.3 – –
Habicht PV
6-24x50 P
Magnification 6-24x
Objective lens diameter (mm) 50
Objective lens diameter (in) 1.97
Exit pupil, diameter (mm) 8.3-2.1
Exit pupil, diameter (in) 0.33-0.08
Eye relief (mm) 80
Eye relief (in) 3.15
Field of view, real (m/100 m) 6.2-1.8
Field of view, real (ft/1000 yds) 18.6-5.4
Field of view, real (degree) 3.5-1
Field of view, apparent (degree) 23.2
Transmission (%) 90
Twilight factor (DIN 58388) 17-35
Impact point correction per click (mm/100 m) 5
Impact point correction per click (in/100 yds) 0.18
Max. elevation/windage adjustment range (ft/100 yd E: 3.6/W: 2.1
Objective filter thread M 55 x 0.75
Length, approx. (mm) 392
Length, approx. (in) 15.43
Weight, approx. (oz) 23.6
Weight, approx. (oz) 18.3 – –
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Re: Swarovski PH6-24X50
Well then, I guess you are looking at 3/16 of an inch per click at 100 yards so that's 6/16 at 200, 9/16 at 300, 12/16 at 400 etc. Run your ballistic chart and figure out how many clicks at each distance to get the right elevation.
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Re: Swarovski PH6-24X50
Well, it is converts to an agle of 0-degrees, 0-minutes, and 10.3-seconds.
Which is very close to 1/20th of a mil. Close as in less than 0.0003% error. Since I only started at two significant figures, I would surmise that it is 1/20th of a mil.
If you use the 3.6-in/100-yd is one mil of deflection that most scope manuals say, then 0.18-inch/3.6-inch, is exactly 1/20th of a mil.
I'm hoping you have a mil dot reticle.
Which is very close to 1/20th of a mil. Close as in less than 0.0003% error. Since I only started at two significant figures, I would surmise that it is 1/20th of a mil.
If you use the 3.6-in/100-yd is one mil of deflection that most scope manuals say, then 0.18-inch/3.6-inch, is exactly 1/20th of a mil.
I'm hoping you have a mil dot reticle.
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Re: Swarovski PH6-24X50
I believe Swarovski uses metric units.
Courtesy of Wicipedia-
Calculating the physical equivalent group size equal to one minute of arc can be done using the equation: equivalent group size = tan(MOA ∕ 60)*distance. In the example previously given and substituting 3600 inches for 100 yards, tan(1 MOA ∕ 60)∙ 3600 inches = 1.0471975511966 inches.
In metric units 1 MOA at 100 meters = 2.90888208665722 centimeters.
2.908 / 2 = 1.454 ( 1/2 minute of arc @ 100 meters)
1.454 / 2 = 0.727 (1/4 minute of arc @ 100 meters)
0.727 / 2 = .3635 (1/8 minute of arc @ 100 meters)
.3635 / 2 = .18175 (1/16 minute of arc @ 100 meters)
So the Swarovski would be said to have 1/16th MOA clicks.
Courtesy of Wicipedia-
Calculating the physical equivalent group size equal to one minute of arc can be done using the equation: equivalent group size = tan(MOA ∕ 60)*distance. In the example previously given and substituting 3600 inches for 100 yards, tan(1 MOA ∕ 60)∙ 3600 inches = 1.0471975511966 inches.
In metric units 1 MOA at 100 meters = 2.90888208665722 centimeters.
2.908 / 2 = 1.454 ( 1/2 minute of arc @ 100 meters)
1.454 / 2 = 0.727 (1/4 minute of arc @ 100 meters)
0.727 / 2 = .3635 (1/8 minute of arc @ 100 meters)
.3635 / 2 = .18175 (1/16 minute of arc @ 100 meters)
So the Swarovski would be said to have 1/16th MOA clicks.
Hold 'em & Squeeze 'em
Re: Swarovski PH6-24X50
Sorry,
i don't have a lot of time, but they are 1/2 cm clicks or 5mm. I missed it right above the .18 in description. Will explain later.
Carlyle
i don't have a lot of time, but they are 1/2 cm clicks or 5mm. I missed it right above the .18 in description. Will explain later.
Carlyle
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Re: Swarovski PH6-24X50
If all else fails, read the instructions!